Not So Rational Integration

Calculus Level 5

I=∫01(2x−1)ln⁡x1−x2 dx\large I = \int_0^1 \dfrac{(2x-1)\ln x}{1-x^2} \, dx

Find the value of the closed form of the above integral II.
Submit your answer as ⌊24I⌋\lfloor 24I \rfloor.

Notation: ⌊⋅⌋ \lfloor \cdot \rfloor denotes the floor function.

Shubhendra Singh by Shubhendra Singh
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