# Not so quick resolution

Let $$n > 0$$ be a product of two different prime numbers.

How many different pairs of positive integers $$(x,y)$$ satisfy:

$n^3 + x^2 = y^2 ?$

The answer to type in: If there are $$a$$ pairs of $$(x,y)$$ for a given even $$n$$ and $$b$$ pairs of $$(x,y)$$ that solve the equation for a given odd $$n$$, then type in the sum of $$a+b$$.

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