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If log100∣x+y∣=12\log_{100}{|x+y|} = \frac{1}{2}log100∣x+y∣=21 and logy−log∣x∣=log1004\log{y} - \log{|x|} = \log_{100}{4}logy−log∣x∣=log1004 .
Then find x+y x+yx+y
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