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∑n=12016n4+n2+1n4+n\large \displaystyle \sum_{n=1}^{2016} \frac{n^{4} + n^{2} + 1}{n^{4} + n} n=1∑2016n4+nn4+n2+1
If the summation above is in the form of AB\dfrac ABBA, where AAA and BBB are coprime positive integers, find A+BA+BA+B.
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