# Kenmotu point

Geometry Level 5

Below is triangle $$ABC$$ with vertices $$A=(0,0), B=(21,0), C=(5,12).$$ The first Kenmotu point for this triangle is $$Q.$$ Find the distance $$AQ$$ to two decimal places.

Note: The first Kenmotu point is the triangle center constructed by inscribing three identical squares such that each square touches two sides of the triangle and all three squares touch at a single common point.

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