# Kidding me?

Geometry Level 3

In the given figure, $$AB=3 \text{ cm}, BC=3\text{ cm}, CD=2\text{ cm}, AD=2\text{ cm}$$. $$\angle ABC= 60^\circ$$. Find the area of the quadrilateral $$ABCD$$.

No trigonometry to be used.

Round off your answer correct to 2 decimal places.
Find your answer in sq cm units.

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