# Kinematics is fun!!!

Thomas throws a stone verticaly upward with velocity $$50 m/s$$. John, who is standing $$278 m$$ above him, throws a stone downward with velocity $$3 m/s$$, two second after the first stone being thrown. Find the height (in meters) of the point where those stones will meet in the air.

Assumes :

• There are no air resistance

• $$g = 10 m/s^2$$

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