Thomas throws a stone verticaly upward with velocity \(50 m/s\). John, who is standing \(278 m\) above him, throws a stone downward with velocity \(3 m/s\), two second after the first stone being thrown. Find the height (in meters) of the point where those stones will meet in the air.

Assumes :

There are no air resistance

\(g = 10 m/s^2\)

×

Problem Loading...

Note Loading...

Set Loading...