# K.T.O.G

**Classical Mechanics**Level pending

\(N\) molecules each of mass \(m\) of gas A and \(2N\) molecules each of mass \(2m\) of gas B are contained in the same vessel which is maintained at temperature \(T\). The **mean square** of the velocity of molecules of **\(B\) type** is denoted by \({ ({ V }_{ RMS-B } })^{ 2 }\) and the mean square of **x-component** of the velocity of **\(A\) type** is denoted by \({ ({ V }_{ RMS-X-A } })^{ 2 }\) .
Find the value of \[\frac { { ({ V }_{ RMS-X-A }) }^{ 2 } }{ { ({ V }_{ RMS-B }) }^{ 2 } }. \]

**Your answer seems reasonable.**Find out if you're right!

**That seems reasonable.**Find out if you're right!

Already have an account? Log in here.