Last Digits In Base 18815
Let \(X\) be the number of distinct possibilities for the units digit of a perfect cube when written in base \(18815\). Find the last three digits of \(X\) (in decimal base).
Details and assumptions
The prime factorization of \(18815\) is \(18815= 5 \times 53 \times 71\).
We're talking about \(18815\) in its decimal representation.
This problem is similar to this one.