# Lazy solving!

Geometry Level 4

If none of $$\alpha, \beta, \gamma,$$ and $$\delta$$ are equal to each other,then $\dfrac{\tan(\gamma-\delta)}{\tan(\alpha-\beta)}+\dfrac{\tan(\delta-\beta)}{\tan(\alpha-\gamma)}+\dfrac{\tan(\beta-\gamma)}{\tan(\alpha-\delta)}+\dfrac{\tan(\gamma-\delta)\tan(\delta-\beta)(\tan(\beta-\gamma)}{\tan(\alpha-\beta)\tan(\alpha-\gamma)(\tan(\alpha-\delta)}\quad=\quad?$

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