Leaky current

The simplest RC circuit consists of a single resistor and capacitor connected around a loop. A capacitor initially charged to \(100~\mbox{V}\) is connected in such a circuit and the voltage across the capacitor drops to \(10~\mbox{V}\) in \(5~\mbox{seconds}\). A second identical resistor is then connected in parallel with the first resistor. How long does it take in seconds for the voltage across the capacitor to further drop to \(1~\mbox{V}\)?

×

Problem Loading...

Note Loading...

Set Loading...