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∫04(x2−4x+5)sin(x−2)2x2−8x+11 dx= ?\large \displaystyle \int_{0}^{4} {\dfrac{(x^{2}-4x+5) \sin (x-2)}{2 x^{2} - 8x +11}} \,dx = \, ?∫042x2−8x+11(x2−4x+5)sin(x−2)dx=?
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