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I=∫0∞ln(1+3844x2)1+961x2 dxI = \large \int_0^{\infty} \dfrac{\ln \left(1 + 3844 x^2 \right)}{ 1 + 961 x^2 } \ \mathrm{d}x I=∫0∞1+961x2ln(1+3844x2) dx
If I=πaln(b)I = \dfrac{\pi}{a} \ln (b) I=aπln(b), then evaluate a+ba+ba+b.
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