# Let's play cricket

There is a hypothetical cricket match going on in kolkata between India vs Australia. Presently there is a spinner of height 2 metre bowling first ball of the over to a right hander.He is bowling a leg stump line, his ball deceives the batsmen and he gets bowled.

In the xyz,co-ordinate space consider the pitch to be the region $$0 \le x \le 20, -2 \le y \le 2,z=0$$

Consider stumps to be the lines

$$0 \le z \le 0.5,x=20,y=0.125$$

$$0 \le z \le 0.5,x=20,y=0$$

$$0 \le z \le 0.5,x=20,y=-0.125$$

The ball is released from the point $$(0,-0.125,2)$$ with a velocity $$30 \hat{i}$$ m/s, also given an angular velocity of $$-\omega \hat{i}, \omega \ge 0$$.

The question is simple, if the maximum value of $$\omega$$, for which the batsmen can get bowled is $$=\frac { a(b+c\sqrt { b } ) }{ d }$$ rad/s where $$a,b,c,d$$ are integers, $$a,d$$ are co-prime,$$b$$ is not divisible by any square prime number then find $$a+b+c+d$$.

Details and Assumptions

1) Assume ball a solid sphere of radius $$0.01 m, g= 10 m{s}^{-2}$$.Consider the pitch to be sufficiently rough and the collision to be elastic.

2) All the co-ordinates are given in metres.

3) If in the trajectory of the ball it is hitting the stumps, consider the batsmen bowled.

4) Consider it as a point mass while calculating it's trajectory

###### Image credit: Wikipedia John Sutton
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