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L'Hospital's Rule? (2)

Calculus Level 3

\[ \large L = \lim_{x\to0} \dfrac{(1+x)^{1/x} - e}{x} \]

Find the value of \(L\).

Clarification: \(e \approx 2.71828\) is the Euler's number.

\[e\] \[-\dfrac{e}{2}\] \[\dfrac{e}{2}\] None of these choices Limit does not exist \[-e\]

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by Sabhrant Sachan

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