# Like Triangles, Then take this!!

Geometry Level 3

Consider two triangles ABC and PQR such that $\angle ADB=\angle BDC=\angle CDA=120^{o}$ In order to rotate the two figures we rotate PRQM by an angle $\theta=\frac{\pi}{3}$clockwise about Q to obtain RR'QM' . Again let X and Y be points on RQ and PQ such that M lies on XY parallel to PR;

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