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limx→π2sinx−(sinx)sinx1−sinx+ln(sinx)= ?\large \displaystyle \lim_{x \to \frac\pi2} \dfrac{\sin x - (\sin x)^{\sin x}}{1-\sin x +\ln (\sin x)}= \ ?x→2πlim1−sinx+ln(sinx)sinx−(sinx)sinx= ?
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