Limit

Calculus Level pending

\[ \lim_{n\to \infty} \left(\sqrt{\left\lfloor {\left( 9n-\frac{1}{6} \right)^2}\right\rfloor} - (9n-1)\right) = \frac{a}{b}\]

Suppose \(a\) and \(b\) are positive integers and \(\gcd(a,b) =1\). Find the value of \(a+b\).

Notation: \( \lfloor \cdot \rfloor \) denotes the floor function.

×

Problem Loading...

Note Loading...

Set Loading...