# Limit

Calculus Level 4

$\displaystyle\lim_{x \rightarrow 0} \left( \dfrac{1}{x\sin x} - \dfrac{1}{\tan^2 x}\right) = \dfrac{a}{b}$

Given that $$a$$ and $$b$$ are positive integers where $$\gcd (a,b)=1$$, find the value of $$a+b$$.

Inspiration

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