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Limit + Integration --> Limtegration!! 😆

Calculus Level 3

\[\large \displaystyle\lim_{t\rightarrow \infty} \frac{\displaystyle\int_{0}^{t} (\tan^{-1}x)^2 \text{dx} }{\sqrt{t^2+1}} = ? \]

\[\frac{\pi}{2}\] \[\frac{\pi}{4}\] \[\frac{\pi^2}{4}\] \[\frac{\pi^2}{2}\]

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by Akhil Bansal

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