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Let us define k0=0k_0=0k0=0 and kn+1=kn+1+kn2k_{n+1}=k_n+\sqrt{1+k_n^2}kn+1=kn+1+kn2.
Find the value of limn→∞(kn2n)\lim_{n \rightarrow \infty} \left(\dfrac{k_n}{2^n}\right)n→∞lim(2nkn)
Also try Limit of a sequence (2) and (3)
Assumptions and Source\textbf{Assumptions and Source}Assumptions and Source
nnn is any non-negative integer.
This is a standard problem in most calculus textbooks for JEE (Advanced)\text{JEE (Advanced)}JEE (Advanced).
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