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limn→∞∑i=2ni2+i−1(i−2)!+(i−1)!+i!+(i+1)!= ?\large{\lim_{n \to \infty} \displaystyle \sum_{i=2}^{n} \frac{i^2 + i - 1}{(i-2)! + (i-1)! + i! + (i+1)!} = \ ?}n→∞limi=2∑n(i−2)!+(i−1)!+i!+(i+1)!i2+i−1= ?
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