Limit till infinity

Calculus Level 5

limnsinπ2nsin2π2nsin(n1)π2nn= ? \lim_{n \rightarrow \infty} \sqrt [n] {\sin{\dfrac{\pi}{2n}}\sin{\dfrac{2\pi}{2n}}\cdots\sin{\dfrac{(n-1)\pi}{2n}}} = \ ?

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