How Do I Find xnx_n First?

Calculus Level 4

Let {xn}\{x_n\} be a sequence such that x1=1, xnxn+1=2nx_1=1,\ x_nx_{n+1}=2n for n1n\ge 1.

Find limnxn+1xnn.\displaystyle \lim_{n\to\infty} \dfrac{|x_{n+1}-x_n|}{\sqrt{n}}.

×

Problem Loading...

Note Loading...

Set Loading...