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limn→∞1n∑r=12nrn2+r2\large \displaystyle \lim_{n \to \infty} \dfrac{1}{n} \sum_{r=1}^{2n} \dfrac{r}{\sqrt{n^{2}+r^{2}}} n→∞limn1r=1∑2nn2+r2r If the limit above exists, find it to three decimal places.
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