Limits can be so unscrupulous

Calculus Level 5

lim⁡x→0(1+x)1/x−ex= ? \lim_{x\to0} \dfrac{(1+x)^{1/x} - e}{x} = \, ?

Round your answer to 1 decimal place.

Clarification

  • e=lim⁡n→∞(1+1n)n≈2.71828\displaystyle e= \lim_{n\to\infty} \left( 1 + \dfrac1n\right)^n \approx 2.71828 .
Benjamin Ononogbu by Benjamin ononogbu
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