Limits can be so unscrupulous
Calculus
Level
4
\[ \lim_{x\to0} \dfrac{(1+x)^{1/x} - e}{x} = \, ? \]
Round your answer to 1 decimal place.
Clarification
- \(\displaystyle e= \lim_{n\to\infty} \left( 1 + \dfrac1n\right)^n \approx 2.71828 \).
by
Benjamin ononogbu