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Limits9

Calculus Level 2

Find \( \displaystyle\lim_{x \rightarrow 0} \displaystyle\frac{x -\sin x}{x- \tan x}\).

\[\frac{1}{2}\] \[\frac{4}{9}\] \[\frac{-1}{2}\] \[\frac{-1}{7}\]

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by samuel ayinde

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