Liquid in a tin can

Classical Mechanics Level pending

\(v\text{ g}\) of liquid at \(100 ^\circ C\) is added into a tin can at \(0 ^\circ C\) weighing \(m\text{ g}\). Given that the heat capacity of the liquid is \(c_L\text{ J/K}\) and that of the tin can is \(c_T\text{ J/K}\), what is the equilibrium temperature \(\theta\) of the system?

Assume the liquid remains as liquid and the tin can remains solid.

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