# Logarithm of the factorial

$\large{ \lfloor \log_x x! } \rfloor = 11814375113$

What is the value of integer $$x$$ such that it satisfy the equation above?

Details and Assumptions

• $$\lfloor x \rfloor$$ is the floor function. ie $$\lfloor 123456.789 \rfloor = 123456$$.
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