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A=∫1∞(1u2−1u4)dulnu \large A = \displaystyle\int_{1}^{\infty} \left(\dfrac{1}{u^2} - \dfrac{1}{u^4}\right) \dfrac{du}{\ln u} A=∫1∞(u21−u41)lnudu
Find the value of eAe^AeA.
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