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The following logarithms are in an arithmetic progression:
log24+log216+log264+⋯+x=42.\log_{2}4 + \log_{2}{16} + \log_{2}{64} + \cdots + x = 42.log24+log216+log264+⋯+x=42.
If xxx can be expressed as log2a,\log_{2}a,log2a, find the value of a.a.a.
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