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Algebra

Positive numbers x,yx, y, and zz satisfy xyz=1081xyz = 10^{81} and (log⁡10x)(log⁡10yz)+(log⁡10y)(log⁡10z)=468(\log_{10}x)(\log_{10} yz) + (\log_{10}y) (\log_{10}z) = 468 .

Find

(log⁡10x)2+(log⁡10y)2+(log⁡10z)2\sqrt {(\log_{10}x)^2 + (\log_{10}y)^2 + (\log_{10}z)^2}

This is the part of this set

Parth Lohomi by Parth Lohomi
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