# Long live Galileo?

**Classical Mechanics**Level 4

Generically, both \(x_B\) and \(t_B\) are functions of *both* \(x_A\) and \(t_A\). In Galilean relativity, \(x_B=X(t_A,x_A,v)\) while \(t_B=t_A\). However there is no mathematical reason why \(t_B\) cannot also be a function of \(x_A\) and \(v\). There is also no reason why \(x_A=x_B\) or \(x_A \neq x_B\) as \(v\rightarrow 0\), as I can shift my origin or not between two coordinate systems/inertial frames.

We now mention an observational fact: the speed of light is experimentally equal to one in every inertial reference frame. Can the following transformation law for \(t_B,x_B\) as a function of \(t_A,x_A\) be true?

\(x_B=x_A-vt_A, t_B=t_A\)

**Your answer seems reasonable.**Find out if you're right!

**That seems reasonable.**Find out if you're right!

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