Looking for peaks.

Calculus Level 5

\[f:[0,1]\rightarrow R \]

\[f'(x) \] is continuous such that \[\int_{0}^{1}f(x)dx=0 \]

If maximum absolute value of f '(x) is 24

Then the absolute value of \[\int_{0}^{x}f(t)dt \]is k \[x\epsilon[0,1] \] find \[8k^2\]

×

Problem Loading...

Note Loading...

Set Loading...