Ok, I know there is a lot of \(2=1\) proof on the internet. And, as you can guess, I **"invented"** mine, so, the only thing you'll have is to enter the incorrect step (indicate the result of the step, so if the incorrect step is between 1 and 2, put 2). Just wanted to say that the title is incorrect, and â€‹no, math is not broken ðŸ˜‚.

\(2 =1+1\)

\(2 = 1 + (âˆ’1) * (âˆ’1)\)

\(2 = 1 + (e^{Ï€i})^2\)

\(2 = (e^{Ï€i})^2 +(e^{Ï€i})^2 \)

\(2 = (e^{\pi i})^4\)

\(\sqrt[4]{2}=e^{Ï€i}\)

\(\sqrt[4]{2} = âˆ’1\)

\(2 = (âˆ’1)^4 \)

\(2 = 1\) ðŸ˜±

×

Problem Loading...

Note Loading...

Set Loading...