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If sin4xa+cos4xb=1a+b {\frac{\sin^{4}x}{a}+\frac{\cos^{4}x}{b}=\frac{1}{a+b}}asin4x+bcos4x=a+b1 then
sin8xa3+cos8xb3=f(a,b){\frac{\sin^{8}x}{a^3}+\frac{\cos^{8}x}{b^{3}}}=f(a,b)a3sin8x+b3cos8x=f(a,b)
find f(1,1)f(1,1)f(1,1)
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