# Method to obtain 40%

In a certain examination $$6$$ papers are set , and to each are assigned $$100$$ marks as a maximum. The number of ways in which a candidate may obtain $$40\%$$ of the whole marks is $\frac { 1! }{ A! } \left\{ \frac { (24B)! }{ (24C)! } -6.\frac { (D44)! }{ (13E)! } +15.\frac { (4F)! }{ (3G)! } \right\}$ Find the value of $A+B+C+D+E+F+G$

Details and Assumptions :

$$A,B,C,D,E,F,G$$ are digits from $$1$$ to $$9$$

×