Mexican Math Olympiad Problem.

Let nn be a natural number and 1=d1<d2<...<dk=n1 = { d }_{ 1 } < {d}_{2} < ... < {d}_{k} = n its divisors, with k3k \ge 3. Find the sum of all nn such that n=d22+d33n = d_2^2 + d_3^3.

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