Forgot password? New user? Sign up
Existing user? Log in
Let nnn be a natural number and 1=d1<d2<...<dk=n1 = { d }_{ 1 } < {d}_{2} < ... < {d}_{k} = n1=d1<d2<...<dk=n its divisors, with k≥3k \ge 3k≥3. Find the sum of all nnn such that n=d22+d33n = d_2^2 + d_3^3n=d22+d33.
Problem Loading...
Note Loading...
Set Loading...