# Minimum distance...

Algebra Level 4

$\begin{cases} { x }^{ 2 }+{ y }^{ 2 }+6x-12y+20=0 \\ { y }^{ 2 }=4x \end{cases}$

The shortest distance between the above curves can be written in the form $$a\sqrt { b } -c$$, then find $$a+b+c$$.

Note: $$a$$,$$b$$ and $$c$$ are positive integers and $$b$$ is not a perfect square.

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