If \(\frac { 4 }{ a } +\frac { 9 }{ b } +\frac { 16 }{ c } +\frac { 36 }{ d } +\frac { 49 }{ e } =8\)

find the minimum value of \(a+b+c+d+e\)

**Details and assumptions**:-

\(\bullet\) \(a,b,c,d,e\) are positive real numbers.

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