The radius of the orbit of an electron in a Hydrogen-like atom is \(4.5a_0\), where \(a_0\) is the bohr's radius.It's orbital angular momentum is \(\frac{3h}{2\pi}\).It is given that *'h'* is Planck's constant and *R* is Rydberg constant.The possible wavelengths when the atom de-excites is/are:-

*1) \(\frac{9}{32R}\)*
*2)\(\frac{9}{16R}\)*
*3)\(\frac{9}{5R}\)*
*4)\(\frac{4}{3R}\)*

**NOTE**:-To type the answer:-**If the answer is 1,4 enter answer as 14,If the answer is 2,3,4 enter answer as 234....means concatenate your options and answer.**

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