Mistakes give rise to Problems- 6

((n!)!)!=n!\large ((n!)!)!= n!

We know that n!=n×(n1)×(n2)×...×2×1n!= n\times (n-1)\times (n-2) \times ... \times 2\times 1. And by definition, 0!=10!=1.

How many integers satisfy the equation above?

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