The vapour pressure of a certain liquid is given by the equation:

logP = 3.54595 - \(\frac{313.7}{T}\) + 1.40655logT

( P- Vapour Pressure in mm of Hg & T- Temperature in Kelvin )

Now find out the molar latent heat of vapourisation as a function of temperature and find its value at a temperature of 80K (in calories).

(Take the value of R to be 8.314 J mol\(^{-1}\) K\(^{-1}\) and 1 calorie to be 4.2 joule)

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