MOSCOW 1952

Geometry Level 4

In \( \triangle{ABC} \), AC=BC, \( \angle C=20^{\circ} \), M is on side AC and N is on the side BC, such that \( \angle BAN=50^{\circ}\), \(\angle ABM=60^{\circ}\). Find \( \angle NMB \) in degrees.

×

Problem Loading...

Note Loading...

Set Loading...