MOSCOW 1952

Geometry Level 4

In $$\triangle{ABC}$$, AC=BC, $$\angle C=20^{\circ}$$, M is on side AC and N is on the side BC, such that $$\angle BAN=50^{\circ}$$, $$\angle ABM=60^{\circ}$$. Find $$\angle NMB$$ in degrees.

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