\[ \begin{array} { l l l l l l l l } & A & B & C & D & E & 9 \\ \times & & & & & & 4 \\ \hline & 9 & A & B & C & D & E \\ \end{array}\]

I have a 6-digit positive integer with a last digit 9. If I move its last digit directly to the front without shifting the other digits, then this new 6-digit number is 4 times the original one.

What is the original 6-digit number?

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