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The angle between the 201520152015-dimensional vectors a⃗\vec{a} a and b⃗\vec{b}b is 30∘30^{\circ} 30∘. Let ∥a⃗∥=8 \|\vec{a} \| = \sqrt{8}∥a∥=8 and ∥b⃗∥=96 \|\vec{b} \| = \sqrt{96}∥b∥=96. Find the value of ∥a⃗−b⃗∥2 \|\vec{a} - \vec{b} \| ^2 ∥a−b∥2.
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