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(1+220)(1+221)(1+222)⋯(1+222015)\large \left( 1+{ 2 }^{ { 2 }^{ 0 } } \right) \left( 1+{ 2 }^{ { 2 }^{ 1 } } \right) \left( 1+{ 2 }^{ { 2 }^{ 2 } } \right) \cdots\left( 1+{ 2 }^{ { 2 }^{ 2015 } } \right) (1+220)(1+221)(1+222)⋯(1+222015)
If the expression above can be expressed as 2A−1 2^A - 12A−1, find the value of log2A\log_2 A log2A.
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