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f(x)=x150+x149+x148+⋯+x+1\large f(x) = x^{150} + x^{149} + x^{148} + \cdots + x +1f(x)=x150+x149+x148+⋯+x+1
Let x1x_{1}x1, x2x_{2}x2 …\ldots… x150x_{150}x150 be the roots of the equation f(x)=0f(x) = 0f(x)=0.
Then find the value of
∑1≤i<j≤1501(1−xi)(1−xj)\ \sum_{1\leq i < j \leq 150} \dfrac{1}{(1-x_{i})(1-x_{j})} 1≤i<j≤150∑(1−xi)(1−xj)1
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