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∫0π/2excos2x dx \large \displaystyle \int_{0}^{\pi/2} e^{x} \cos^{2} x \, dx ∫0π/2excos2xdx
It is given that the above integral can be expressed in the form aebπ/c−df\large \dfrac{a e^{{b \pi}/{c}}-d}{f}faebπ/c−d where a,b,c,d,f a, b, c, d, f a,b,c,d,f are positive integers, gcd(a,f)=gcd(b,c)=1\gcd(a,f) = \gcd(b,c) = 1gcd(a,f)=gcd(b,c)=1.
Find the value of a+b+c+d+fa+b+c+d+fa+b+c+d+f.
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