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m−⌊m2005⌋=2005\large m - \left\lfloor \frac{m}{2005} \right\rfloor = 2005 m−⌊2005m⌋=2005
Find mmm that satisfies the equation above.
Notation: ⌊⋅⌋ \lfloor \cdot \rfloor ⌊⋅⌋ denotes the floor function.
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